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15 Dec 2020, 05:00
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
62% (01:04) correct
38%
(01:13)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
If f(x) = x + 3, then the line shown in the xy-plane above is the graph of
(A) f(x)
(B) f(x – 6)
(C) f(x + 6)
(D) f(x + 3)
(E) f(x – 3)
Attachment:
2020-12-15_14-20-31.png [ 13.86 KiB | Viewed 2080 times ]
callmeDP
Joined: 25 Oct 2020
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15 Dec 2020, 05:09
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Couple of things stand out seeing the graph in the question,
1. Line passes through (0,0) and (6,6)
2. C = 0
3. m = 1
Possible equation: y= x ...... (1)
Now, f(x) = x+3 ....... (2); then you are asked the equation of the line in the graph in terms of function given.
From (1) & (2), you can see that we need to get rid of "3" from the f(x)
Best way is given by E. >> f(x -3) = (x-3) + 3 = x
IMO E
1. Line passes through (0,0) and (6,6)
2. C = 0
3. m = 1
Possible equation: y= x ...... (1)
Now, f(x) = x+3 ....... (2); then you are asked the equation of the line in the graph in terms of function given.
From (1) & (2), you can see that we need to get rid of "3" from the f(x)
Best way is given by E. >> f(x -3) = (x-3) + 3 = x
IMO E
15 Dec 2020, 05:13
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Bunuel
Equation of a line = y = mx + c
Since the line is passing through the origin, c = 0 and y = mx
Also given that the line passes through the points (6,60. Putting it in the above equation, 6 = m*6. Therefore m = 1 and the equation of the line is y = x
Now if the function is defined as f(x) = y = x + 3, then y = x is defined by f(x - 3)
Option E
Arun Kumar
