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16 Dec 2020, 06:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:36) correct
20%
(02:16)
wrong
based on 45
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A park is in the shape of a square, a triangle, and a semicircle, attached as in the diagram below. If the area of the square is 144 and the perimeter of the triangle is 28, find the perimeter of the park.
(A) 52 + 12π
(B) 52 + 6π
(C) 40 + 6π
(D) 34 + 12π
(E) 32 + 6π
Attachment:
2020-12-15_16-07-34.png [ 32.42 KiB | Viewed 2880 times ]
16 Dec 2020, 07:25
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Bunuel
The area of the square is 144. Therefore each side = 12.
The perimeter of the triangle, includes the side of the square. The length of the remaining 2 sides = 28 - 12 = 16
The base of the semicircle is the side of the square.
Therefore the radius of the semicircle = 6 and the circumference = 2πr/2 = 6π
The perimeter of the park is the circumference of the semicircle + 2 sides of the square + 2 sides of the tringle
= 12 + 12 + 16 + 6π
= 40 + 6π
Option C
Arun Kumar
16 Dec 2020, 12:56
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Side of a square= sqrt (144) = 12
Sum of 2 outer sides of triangle= 28-12= 16
Semi circle circumference= Pie*6
Total perimeter of park= 12*2 + 16+ 6*Pie = 40+ 6*pie
Ans. C.
Sum of 2 outer sides of triangle= 28-12= 16
Semi circle circumference= Pie*6
Total perimeter of park= 12*2 + 16+ 6*Pie = 40+ 6*pie
Ans. C.
