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\(x+y=z.\\
\)
\(\frac{m+n+p}{3}=q\).

\(m+n+p=3q\).

Therefore, \(x+y+m+n+p= z+3q\)

Therefore, the OA is B.
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x + y = z

=> m + n + p = 3q

=> x + y + z + m + n + p = z + 3q

Answer B
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