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Bunuel
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two sides of a triangle are 3 and 4 and third side is x.

As, Sum of 2 sides is greater than 3rd side.
So, x (max)= 3+4= 7, And, x (min)= 4-3= 1

Ans. D. :)
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Sum of two sides of a triangle should be greater than the third side and the difference of any two sides of a triangle should be less than the third side.
Therefore, 3+4=7
4-3=1

1<x<7

IMO: D
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IMO D

4+3 = 7
4-3 = 1

1 < x < 7
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Bunuel
If two sides of a triangle are 3 and 4 and the third side is x, then

(A) x = 5
(B) x > 7
(C) x < 7
(D) 1 < x < 7
(E) x > 7 or x < 1

third side of ∆ greater than +ve difference of 4,3 and less than sum of 4,3
i.e
1<x<7
option D
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Bunuel
If two sides of a triangle are 3 and 4 and the third side is x, then

(A) x = 5
(B) x > 7
(C) x < 7
(D) 1 < x < 7
(E) x > 7 or x < 1

A (third side) side of a triangle is less than the sum of the other two sides and greater than the subtraction of the other two sides.

So, \(4-3< x < 4+3\)

\(=1 < x < 7\)

The answer is \(D\)
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Bunuel
If two sides of a triangle are 3 and 4 and the third side is x, then

(A) x = 5
(B) x > 7
(C) x < 7
(D) 1 < x < 7
(E) x > 7 or x < 1
Solution:

Recall that the length of the third side of a triangle is greater than the (positive) difference between the lengths of the other two sides and less than the sum of their lengths. Therefore, we have:

4 - 3 < x < 4 + 3

1 < x < 7

Answer: D
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