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17 Dec 2020, 04:15
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
88% (01:20) correct
12%
(00:55)
wrong
based on 33
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History
Date
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The diameter of a circle is increased by 50%. The area is increased by
(A) 50%
(B) 100%
(C) 125%
(D) 200%
(E) 250%
(A) 50%
(B) 100%
(C) 125%
(D) 200%
(E) 250%
17 Dec 2020, 06:51
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Bunuel
Let the original diameter = 20.
Then the radius = 10 and area = \(\pi r^2 = 100\pi\)
After an increase of 50%, the new diameter = 1.5 * 20 = 30.
Then the radius = 15 and area = \(\pi r^2 = 225\pi\)
The % increase = \(\frac{Difference}{Smaller \space value} * 100 = \frac{125}{100} * 100 = 125\)%
Option C
Arun Kumar
17 Dec 2020, 06:54
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If d increased by 50 %, then r also increased by 50 %.
\(Area = 2πr^2\)
New Area \(= (1.5)^2 2πr^2 = 2.25*2πr^2\)
Increase in Area (percentage) \(= (2.25 - 1.00)*100 = 125\)
Ans (C) 125%
\(Area = 2πr^2\)
New Area \(= (1.5)^2 2πr^2 = 2.25*2πr^2\)
Increase in Area (percentage) \(= (2.25 - 1.00)*100 = 125\)
Ans (C) 125%
