If the average of x and y is m, and z = 2m, what is the average of x

Question

If the average of x and y is m, and z = 2m, what is the average of x, y, and z?

(A) m
(B) 2m/3
(C) 4m/3
(D) 3m/4
(E) 3/(4m)

Nipungupta9081 · Answer

IMO C

Average = Sum of terms / No. of terms 
M = X + Y / 2 
2m = X + Y ------ (1)

And Z = 2m -----( 2 )

Average = x + y + z / 3

putting values

= 2m + 2m / 3 = 4m /3

MBAAD21 · Answer

Given, average of x and Y is m 
i.e x+y/2= m
 x+y=2m ......1.
 z= 2m..........2.

avg. of x+y+z/3= 2m+2m/3
 
Therefore 4m/3

IMO: C

Abhishek009 · Answer

x + y = 2m

So,  \frac{x + y + z}{3} = \frac{2m + 2m}{3} = \frac{4m}{3} , Hence, Answer must be (C)

TarunKumar1234 · Answer

Given, 2m = x+y = z, So, (x+y+z)/3= (2m +2m)/3= 4m/3. Ans. C.

rocky620 · Answer

x+y = 2m
z = 2m
so (x+y+z)/3 = 4m/3

Option C

MathRevolution · Answer

x + y = 2m

=>  \frac{(x + y + z ) }{3} :  \frac{(2m + 2m) }{ 3}  =  \frac{4m}{3}

Answer: C

ScottTargetTestPrep · Answer

Solution:
 
Since the average of x and y is m, the sum of x and y is 2m. Since z = 2m, the average of x, y, and z is:

(x + y + z) / 3 = (2m + 2m) / 3 = 4m/3

Answer: C

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