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22 Dec 2020, 04:00
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:41) correct
19%
(01:21)
wrong
based on 37
sessions
History
Date
Time
Result
Not Attempted Yet
The cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15. The cost of 2 cookies, 3 doughnuts, and 4 boxes of doughnut holes is $7.20. What is the cost of a box of doughnut holes?
(A) $.85
(B) $.95
(C) $1.05
(D) $1.15
(E) $1.25
(A) $.85
(B) $.95
(C) $1.05
(D) $1.15
(E) $1.25
22 Dec 2020, 04:21
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SOLUTION :
Given:
4 cookies + 6doughnuts + 3 doughnut holes boxes = $8.15......(i)
2 cookies + 3 doughnuts + 4 doughnut holes boxes= $7.20.....(ii)
Multiply (ii) by 2 we have
4 cookies + 6 doughnuts + 8 doughnut hole boxes = $14.4..(iii)
Subtracting (i) from(iii) we have
5 doughnut hole boxes = $6.25
=> 1 doughnut hole box= 6.25/5 =$1.25 (OPTION E)
Hope this helps
Miss Devmitra Sen(Math)
Given:
4 cookies + 6doughnuts + 3 doughnut holes boxes = $8.15......(i)
2 cookies + 3 doughnuts + 4 doughnut holes boxes= $7.20.....(ii)
Multiply (ii) by 2 we have
4 cookies + 6 doughnuts + 8 doughnut hole boxes = $14.4..(iii)
Subtracting (i) from(iii) we have
5 doughnut hole boxes = $6.25
=> 1 doughnut hole box= 6.25/5 =$1.25 (OPTION E)
Hope this helps
Miss Devmitra Sen(Math)
22 Dec 2020, 06:53
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Cookies=\(c\), Doughnuts=\(d\). Doughnut holes=\(dh\).
\(4c+6d+3dh=8.15\) - ---- Equation 1.
\(2c+3d+4dh=7.20\) - ---- Equation 2.
Multiplying equation 2 by 2 and then subtracting equation 1 from it.
\(4c+6d+8dh=14.40\)
\(4c+6d+3dh= 8.15\)
- - -
-----------------------
\(0+ 0+ 5dh= 6.25.\)
\(dh\)=\(\frac{6.25}{5}\) => \(1.25\).
Therefore, the OA is E.
\(4c+6d+3dh=8.15\) - ---- Equation 1.
\(2c+3d+4dh=7.20\) - ---- Equation 2.
Multiplying equation 2 by 2 and then subtracting equation 1 from it.
\(4c+6d+8dh=14.40\)
\(4c+6d+3dh= 8.15\)
- - -
-----------------------
\(0+ 0+ 5dh= 6.25.\)
\(dh\)=\(\frac{6.25}{5}\) => \(1.25\).
Therefore, the OA is E.
