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29 Dec 2020, 10:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
87% (01:12) correct
13%
(01:35)
wrong
based on 52
sessions
History
Date
Time
Result
Not Attempted Yet
The length of a walk-in closet is 4 feet greater than its width. Its area is 60 square feet. How many feet wide is the closet?
(A) 4
(B) 6
(C) 8
(D) 10
(E) 12
(A) 4
(B) 6
(C) 8
(D) 10
(E) 12
29 Dec 2020, 10:06
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Using equations,
\(x(x+4)=60\)
\(x^2+4x-60=0\)
\((x+10)(x-6)=0\)
\(x=-10,6\)
Width, \(x=6\)
Choosing numbers, if \(x=6, (x+4)=10; Area=6*10=60\)
IMO Ans B
\(x(x+4)=60\)
\(x^2+4x-60=0\)
\((x+10)(x-6)=0\)
\(x=-10,6\)
Width, \(x=6\)
Choosing numbers, if \(x=6, (x+4)=10; Area=6*10=60\)
IMO Ans B
29 Dec 2020, 10:51
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Quote:
Using the options:
(a) When width is 4, length is 8, area is 32 Incorrect
(b) When width is 6, length is 10, area is 60 Correct
B is correct
