For what values of m does the equation x^2 − x + m = 0 possess no real

Question

For what values of m does the equation x^2 − x + m = 0 possess no real roots? A. m > 1/4 B. m > 0 C. m = 0 D. m < -1/4 E. m < -4

Kinshook · Answer

Asked: For what values of m does the equation x^2 − x + m = 0 possess no real roots?

For no real roots:
b^2-4ac<0
1-4m<0
m>1/4

IMO A

Posted from my mobile device

Fdambro294 · Answer

Given a Quadratic Equation of the Form:

A(x)^2 + B(x) + C = 0

——where A , B , and C are constant Values——

If the Discriminant is < 0, there will be no roots that satisfy the quadratic equation.

For what Values of M will:

(B)^2 - 4(A)(C) < 0

A = +1
B = -1
C = M

(-1)^2 - (4)(1)(M) < 0

1 - 4M < 0

1 < 4M

M > 1/4

A

Posted from my mobile device

quaes · Answer

For no real roots:
 4ac > b^2 
=> 4*1*m > (-1)^2 
=> 4m > 1
=> m > 1/4

Abhishek009 · Answer

-1^2 - 4*1*m < 0 Or, 1 -4m < 0 Thus, 4m > 1 , Hence m > \frac{1}{4} , Answer must be (A)

Prep Toolkit