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Bunuel
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X rate of 1- day work: \(\frac{1}{12}\) and he finishes \(\frac{2}{3}\) of the work.

Reamining work: \(1 - \frac{2}{3} = \frac{2}{3}\)

Y rate: \(\frac{1}{10} * \frac{1}{12} = \frac{1}{120}\)

=> \(\frac{1}{3}\) work = \(\frac{1}{120}\) rate

=> Rate * Time= Work

=> \(\frac{120 }{ 3}\) = 40 hours.

Answer C
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Let Total work: 120 units
Speed of X: 10 units(since his rate is 12 hours to complete the work)
Speed of Y : 1 units per hour(1/10 of X)

Work Finished by X= 120*2/3=80
Work Left= 120-80=40

Time taken by Y
40/1= 40 hours
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