Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Jun 1111:00 AM EDT
-01:00 PM EDT
TTP GMAT OnDemand gives serious students 400+ hours of expert video instruction, the full TTP course, AI support, weekly office hours, and a 715+ score guarantee—all built for elite GMAT score improvement.
Jun 2207:30 PM EDT
-09:30 PM EDT
Master the GMAT with expert live instruction, a personalized study plan, and real-time support. Includes 40 hours of online classes plus 6 months of access to the TTP GMAT OnDemand video course. Class date: Mon/Wed June 22, 2026 →August 26, 2026
13 Jan 2021, 09:15
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
43% (01:20) correct
58%
(01:31)
wrong
based on 40
sessions
History
Date
Time
Result
Not Attempted Yet
A sector of a circle of radius 5 cm is recast into a right circular cone of height 4 cm. What is the volume of the resulting cone?
A. \(100 π\) cm^3
B. \(33 π\) cm^3
C. \(32 π\) cm^3
D. \(12 π\) cm^3
E. \(4 π\) cm^3
A. \(100 π\) cm^3
B. \(33 π\) cm^3
C. \(32 π\) cm^3
D. \(12 π\) cm^3
E. \(4 π\) cm^3
13 Jan 2021, 09:31
Kudos
Bookmarks
Given, a section of circle is made to right circular cone.
So, r = radius of cone = sqrt (5^2-4^2) = sqrt(9) = 3
Volume of circular cone = 1/3 * Pie *r^2 *h = 1/3 * pie *3^2 *4 = 12*pie cm^3
I think D.
So, r = radius of cone = sqrt (5^2-4^2) = sqrt(9) = 3
Volume of circular cone = 1/3 * Pie *r^2 *h = 1/3 * pie *3^2 *4 = 12*pie cm^3
I think D.
13 Jan 2021, 22:30
Kudos
Bookmarks
The radius\((r_{ci})\) of the circle will be the slant height\((l)\) of the cone when recasted, so the slant height \((l)\) of the cone \(=5 cm\)
Therefore, using Pythagoras theorem, the radius of the cone,\( r_{co} =\sqrt{l^2-h^2}=\sqrt{5^2-4^2}=\sqrt{9}=3\)
\(V_{cone}=\frac{1}{3} π r^2 h=\frac{1}{3} π 3^2 *4=12π\)
Ans D
Therefore, using Pythagoras theorem, the radius of the cone,\( r_{co} =\sqrt{l^2-h^2}=\sqrt{5^2-4^2}=\sqrt{9}=3\)
\(V_{cone}=\frac{1}{3} π r^2 h=\frac{1}{3} π 3^2 *4=12π\)
Ans D
Attachments
cone.png [ 22.43 KiB | Viewed 10464 times ]
