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16 Jan 2021, 12:15
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:38) correct
12%
(02:18)
wrong
based on 201
sessions
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If \(\sqrt{x} = 25\), then \(x^3 – x^ 2 =\)
A. \(5^{12}\)
B. \(5^{20}\)
C. \(6(5^5)\)
D. \(5^4(5^2 + 1)\)
E. \(5^8(5^4 − 1)\)
A. \(5^{12}\)
B. \(5^{20}\)
C. \(6(5^5)\)
D. \(5^4(5^2 + 1)\)
E. \(5^8(5^4 − 1)\)
16 Jan 2021, 16:11
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Squaring both sides to get X=25^2 -> (5^2)^2 -> 5^4
X^2 = (5^4)^2 -> 5^8
X^3 = (5^4)^3) -> 5^12
so, X^3 - X^2 = 5^12 - 5^8 = 5^8(5^4 - 1) = E
X^2 = (5^4)^2 -> 5^8
X^3 = (5^4)^3) -> 5^12
so, X^3 - X^2 = 5^12 - 5^8 = 5^8(5^4 - 1) = E
16 Jan 2021, 22:12
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Bunuel
When \(\sqrt{x} = 25\), then \(x = 25^2 = 5^4\)
The value of the expression \(x^3 – x^ 2 \) is \( 5^{12} – 5^8 \) which can be further simplified as \( 5^8(5^4 - 1)\) (Option E)
