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I assumed CP to be 100
and let the price at which it is regularly sold to be X

but in the loss example, 100-X/2 = 10
X=180

Profit = 180-100
=80

Profit % = 80/100 = 80%
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I assumed CP to be 100
and let the price at which it is regularly sold to be X

but in the loss example, 100-X/2 = 10

X=180

Profit = 180-100
=80

Profit % = 80/100 = 80%
can you please explain the highlighted portion
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Saransh123
wishmasterdj
I assumed CP to be 100
and let the price at which it is regularly sold to be X

but in the loss example, 100-X/2 = 10

X=180

Profit = 180-100
=80

Profit % = 80/100 = 80%
can you please explain the highlighted portion

X here is assumed to be the selling price.

So, if profit, it would be X-100, and
if loss, it would be 100-x

Now, in the question it is given that if he sold it at half that price (which is X/2), he incurs a loss of 10%

Therefore either 100-X/2 = 10, OR X/2-100 = -10
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Thank You soo much wishmasterdj for clearing my doubt, here comes a kudos for you
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Let the cost price be 20.

If loss % is 10%, then S.P. is 18

Now selling for S.P. = 36 will give us a profit of \(\frac{(36-20)}{20} * 100 = 80%\)

Answer A
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