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08 Feb 2021, 08:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:54) correct
20%
(02:10)
wrong
based on 222
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One type of liquid contains 35% of milk, the other contains 40% of milk. A can is filled with 15 parts of the first liquid and 10 parts of the second liquid. Find the percentage of milk in the new mixture.
(A) 31
(B) 33
(C) 35
(D) 36.5
(E) 37
(A) 31
(B) 33
(C) 35
(D) 36.5
(E) 37
08 Feb 2021, 11:12
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Answer E.
Liquid Type I has 35% milk and 65% water.
Liquid Type II has 40% milk and 60% water.
In the Can, there are 15 parts of liquid I, 'parts' is an abstract term, lets just say 15 Liters of Liquid Type 1, and 10 liters of Types II make up the can. out of the 15 liters of liquid I, 35% is milk, 0.35 x 15 = 5.25, out of the 10 liters of liquid II, 40% is milk, 0.4 x 10= 4, so total pure milk is (5.25+4) L out of the 25L can.
9.25/25 = 0.37, hence answer E
Liquid Type I has 35% milk and 65% water.
Liquid Type II has 40% milk and 60% water.
In the Can, there are 15 parts of liquid I, 'parts' is an abstract term, lets just say 15 Liters of Liquid Type 1, and 10 liters of Types II make up the can. out of the 15 liters of liquid I, 35% is milk, 0.35 x 15 = 5.25, out of the 10 liters of liquid II, 40% is milk, 0.4 x 10= 4, so total pure milk is (5.25+4) L out of the 25L can.
9.25/25 = 0.37, hence answer E
