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01 Mar 2021, 03:15
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C
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Difficulty:
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Question Stats:
80% (01:25) correct
20%
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wrong
based on 79
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A committee of 3 is to be formed from 5 persons A, B, C, D, and E. If all persons are equally likely to be elected, what is the probability that A is not on the committee?
A. 1/5
B. 1/3
C. 2/5
D. 3/5
E. 2/3
A. 1/5
B. 1/3
C. 2/5
D. 3/5
E. 2/3
01 Mar 2021, 05:44
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If A is not in the committee, then the number of ways of choosing 3 people out of 4 = 4C3 = 4 ways
Total number of ways = 5C3 = 5C2 = 5 * 4 / 2 = 10 ways
probability = Favorable outcomes / Total Outcomes = 4 / 10 = 2/5
Option C
Arun Kumar
Total number of ways = 5C3 = 5C2 = 5 * 4 / 2 = 10 ways
probability = Favorable outcomes / Total Outcomes = 4 / 10 = 2/5
Option C
Arun Kumar
01 Mar 2021, 10:35
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Selecting 3 person out of 5: \(^5{C_3} = 10\) - Total outcome
Selecting 3 person out of 4: \(^4{C_3} = 4\) - Desired [A not in committee]
Probability: \(\frac{4}{10} = \frac{2}{5}\)
Answer C
Selecting 3 person out of 4: \(^4{C_3} = 4\) - Desired [A not in committee]
Probability: \(\frac{4}{10} = \frac{2}{5}\)
Answer C
