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04 Mar 2021, 08:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
59% (01:59) correct
41%
(02:21)
wrong
based on 174
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History
Date
Time
Result
Not Attempted Yet
In how many ways can 8 boys be divided into two unequal sets? (Assume that a group consisting of 0 boys is not allowed)
A. 84
B. 92
C. 93
D. 105
E. 197
A. 84
B. 92
C. 93
D. 105
E. 197
04 Mar 2021, 18:28
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The different unequal groups are (1,7), (2,6) and (3,5)
(8C1 * 7C7) + (8C2 * 6C6) + (8C3 * 5C5) = 8 + 28 + 56 = 92
Option B
Arun Kumar
(8C1 * 7C7) + (8C2 * 6C6) + (8C3 * 5C5) = 8 + 28 + 56 = 92
Option B
Arun Kumar
