A mixture of a certain quantity of milk with 16 L of water is worth 12

Question

A mixture of a certain quantity of milk with 16 L of water is worth 128 per litre. If pure milk be worth 144per litre, how much milk is there in the mixture ?

(A) 110 L 
(B) 120 L 
(C) 128 L 
(D) 163 L
(E) 173 L

globaldesi · Answer

using alligation method

0 144
 128
16 128
thus ratio of water and milk is 1:8
given  \frac{1}{9} (t) = 16 
t =  16*9 
milk =  \frac{8}{9}(T) 
=  \frac{8*16*9}{9} 
or 128
C IMO

AnirudhaS · Answer

you have literally solved it here, step highlighted.
Don't need to do any further steps, as it does say that there are 16 litres of water, so there must be 128 lts of milk.

**Also this is assuming water is FREE!

stne · Answer

Let there be  x  L of pure milk so total cost should be  144*x

But after adding 16L of water costs becomes 128/L

So  \frac{144*x}{x+16} = 128

x=128

Hope it's clear.

astiles67 · Answer

Missing price of water is what got me. I had   for that variable and could not solve.

Would GMAT make a problem with that kind of ambiguity or would it clarify a price for water?

A mixture of a certain quantity of milk with 16 L of water is worth 12

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A mixture of a certain quantity of milk with 16 L of water is worth 12

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