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08 Mar 2021, 08:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
89% (02:19) correct
11%
(02:47)
wrong
based on 152
sessions
History
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There are two jars – A and B containing a mixture of milk and water only. Jar A has 8 litres of mixture which has 25% water. Jar B has 14 litres of mixture, Milk and water in jar B are in the respective ratio of 6 : 1. The content of both the jar are mixed. What is the percentage of water in the new mixture?
A. \(13 \frac{2}{3}\)
B. \(14 \frac{1}{9}\)
C. \(15 \frac{1}{9}\)
D. \(16 \frac{1}{9}\)
E. \(18 \frac{2}{11}\)
A. \(13 \frac{2}{3}\)
B. \(14 \frac{1}{9}\)
C. \(15 \frac{1}{9}\)
D. \(16 \frac{1}{9}\)
E. \(18 \frac{2}{11}\)
09 Mar 2021, 09:31
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Bunuel
Jar A has 2 L water and 6 L milk. Jar B has \(\frac{6}{6+1}*14 = 12\) L milk and \(14 - 12 = 2\) L water.
After mixing, we have 4 L water and 18 L milk.
Therefore the percentage of water is \(\frac{4}{4+18} = \frac{2}{11} * 100\% = \frac{200}{11}\% = 18\frac{2}{11}\%\)
05 May 2021, 02:24
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Bunuel could You please adjust the answer E, it shall be 18-2/11%. Thanks
