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11 Mar 2021, 07:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
59% (01:56) correct
41%
(01:47)
wrong
based on 46
sessions
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Not Attempted Yet
In a trapezium, the diagonals intersect at point O. The ratio of the length of one of the diagonals from one vertex of the trapezium to the point O, to its entire length is 2 : 5. What is the ratio of its parallel sides ? (smaller side : larger side),
(A) 2 : 8
(B) 2 : 3
(C) 2 : 5
(D) 2 : 7
(E) 2 : 9
(A) 2 : 8
(B) 2 : 3
(C) 2 : 5
(D) 2 : 7
(E) 2 : 9
priyachandank
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Joined: 08 Mar 2020
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WE:Corporate Finance (Consulting)
04 Apr 2021, 22:40
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since the diagonals bisect each other, i used pythagorean formula to find the lengths.
total diagonal length 5 units; shorter point is 2 units, longer one as 3 units.
root(2^2+2^2)/ root(3^2+3^2)= 4/9; and the options do not match.
Hi VeritasKarishma ,Do you mind helping me, please? Thank you.
total diagonal length 5 units; shorter point is 2 units, longer one as 3 units.
root(2^2+2^2)/ root(3^2+3^2)= 4/9; and the options do not match.
Hi VeritasKarishma ,Do you mind helping me, please? Thank you.
06 Apr 2021, 00:09
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priyachandank
Diagonals do not bisect each other. Look at the figure of trapezium. Diagonal intersect at O such that
CO:CA = 2 : 5.
We need ratio of CD:AB.
Attachment:
Screenshot 2021-04-06 at 12.32.19.png [ 42.82 KiB | Viewed 4307 times ]
Draw PQ parallel to AB and CD.
Triangles COQ and CAB are similar (all angles equal).
CO:CA = 2:5 so OQ:AB = 2:5 too (ratio of all sides are same in similar triangles)
Also CQ:CB = 2:5 which means BQ:BC = 3:5.
Triangles BOQ and BDC are similar (all angles equal).
Since BQ:BC = 3:5, so OQ:CD = 3:5
OQ:AB = 2:5 and OQ:CD = 3:5 which means OQ:AB:CD = 6:15:10.
So CD:AB = 2:3
Answer (B)
