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Bunuel
An Ice-cream parlor buys milk-cream cartons, each containing 5/2 cups of milk-cream. If the restaurant uses 1/2 cup of the milk-cream in each serving of its ice-cream, what is the least number of cartons needed to prepare 98 servings of the ice-cream?

(A) 9
(B) 19
(C) 20
(D) 21
(E) 24

\(98\) servings will require \(\frac{1}{2}*98 = 49\) cups of milk.

\(48\) cups will require \(\frac{2}{5}*49 = \frac{98}{5} = 19 \frac{3}{5}\) Cartons.

or Minimum \(20\) cartons are required

Ans-C

Hope it's clear.
-----------------------------------------------

Hi this isn't clear. Can you explain again?

summerbummer,



We need to prepare \(98\) servings of ice cream

If each serving requires \(\frac{1}{2}\) cup of milk cream.

So what is total amount of Milk cream required ?

Total amount required = amount required in each serving * number of serving

\(\frac{1}{2}*98 = 49\)

Hence we need Total \(49\) cups of Milk cream

Now each carton has \( \frac{5}{2}\) cups of Milk cream.

So how many cartons will be required so that we can get total 49 cups of milk cream?

Total Milk cream = Milk cream in each carton * No. of cartons


\(49 = \frac{5}{2} \)* No. of cartons

No of cartons = \(= \frac{49 * 2}{5} = \frac {98}{5}= 19 \frac{3}{5}\)

Since we can only have cartons in whole numbers we need a minimum of \(20\) cartons to serve \( 98 \) ice creams .

If anything still remains unclear , please quote the exact line which is unclear so that I can a better assist you. Thank you.
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