Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
17 Apr 2021, 14:29
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
65% (02:09) correct
35%
(02:26)
wrong
based on 26
sessions
History
Date
Time
Result
Not Attempted Yet
The right circular cone pictured below is cut horizontally at the midpoint of its height. If the smaller piece has a height of 3 and a volume of 9*pi, what is the volume of the larger piece?
A. 12*pi
B. 21*pi
C. 63*pi
D. 216*pi
E. 284*pi
A. 12*pi
B. 21*pi
C. 63*pi
D. 216*pi
E. 284*pi
Attachments
image0 (5).jpeg [ 338.69 KiB | Viewed 1262 times ]
17 Apr 2021, 15:09
Kudos
Bookmarks
Cone volume = (area base * height)/3 = (pi * radius^2)/3, so the botton cone has a base of radius 3.
The upper circle has double radius than the botton one. So the total cone has an area of 72pi (36pi * 6/3).
Substracting both cones: 72pi - 9pi = 63pi.
Answer C
The upper circle has double radius than the botton one. So the total cone has an area of 72pi (36pi * 6/3).
Substracting both cones: 72pi - 9pi = 63pi.
Answer C
Moderator:
