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My route:
Divide the numbers 45/54=5/6
Formula: S*T=D
45*6=270
54*5=270
Difference is 1 hour or 60 minutes
Time taken for every stop= 60/6=10 (D)
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Normally without stopping:

In 60 minutes —————-> bus can travel 54 km


Thus, without stopping and constantly driving:

In 1 min ————-> bus can travel (54/60) = 9/10 km


Then we are told when the bus stops, in 60 minutes (1 hour), it is only able to cover 45 km

We can find the amount of time the bus spends driving in that 60 minutes. The rest of the time must have been spent stopping.

So over the course of this 1 hour (60 min):


If in 1 min while driving —————> bus can travel (9/10) km

Then in M minutes ————> bus is able to travel 45 km

1 / (9/10) = M / 45

M = 45 / (9/10)

M = 450 / 9

M = 50 minutes

This means the over the course of the 1 hour when the bus makes the stops, it must have spent 50 minutes driving at its usual speed.

The other 10 minutes must have been when the bus was stopped.

(D) 10 minutes

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54 km without stopping in 60
45 km with stopping in 60min

length of stopping platforms = 54-45= 9km

it can travel 54km in 60 min
9km in (60*9)/54 min =10 minutes
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I've seen a couple of these questions pop up and I saw a really helpful method in another forum so I thought I'd share:

54kph without stoppages
45kph with stoppages

54-45=9

9km of distance is lost

therefore the bus is halted for 9/54 or 1/6 hours: 10 minutes per hour

Bunuel
Excluding stoppages, speed of the bus is 54 kmph and including stoppages it is 45 kmph. For how many minutes does the bus stop per hour?

A. 4
B. 6
C. 8
D. 10
E. 12
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Approach 1: The "Distance Gap" Method (Conceptual)
This method focuses on how much distance is lost due to the stops.

Analyze the distance in one hour:
If the bus does not stop, it covers 54 km in 60 minutes.
If the bus does stop, it only covers 45 km in 60 minutes.

Calculate the "Lost" Distance:
The bus covered 9 km less than its full potential (54−45=9 km).

Calculate the time required to cover that gap:
We need to find out how long it takes the bus to travel those "lost" 9 km when it is actually moving at its normal speed (54 kmph).

Time = Distance/Speed
Time = 9/54 = 1/6 hour

Convert to minutes:
1/6 × 60 minutes =10 minutes

Conclusion: The 10 minutes the bus would have spent driving those 9 km were instead spent at a standstill.



Approach 2: The Speed Ratio Formula
There is a direct formula used for "stoppage" problems that helps you get the answer in seconds:

Stop time per hour = {(Fast Speed−Slow Speed)/Fast Speed} * 60
= {(54 - 45)/54} * 60
= 10 minutes
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Many ways to solve. You can simply subtract and take wrt to 54 like profit and loss problems. I like it super intuitive like this:

Take 54km total distance
1st takes 1hr
2nd takes 1.2 hrs or 12 mins extra
This 12 mins extra is for a period of 72 mins
Hence for per hour it is 12/72*60 = 10 mins

Bunuel
Excluding stoppages, speed of the bus is 54 kmph and including stoppages it is 45 kmph. For how many minutes does the bus stop per hour?

A. 4
B. 6
C. 8
D. 10
E. 12
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