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27 Apr 2021, 05:15
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Difficulty:
55%
(hard)
Question Stats:
70% (02:32) correct
30%
(02:53)
wrong
based on 198
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A, B and C can do a piece of work in 11 days, 20 days, and 55 days, respectively, working alone. How soon can the work be done if A is assisted by B and C on alternate days?
(A) 7 days
(B) 8 days
(C) 9 days
(D) 10 days
(E) 11 days
(A) 7 days
(B) 8 days
(C) 9 days
(D) 10 days
(E) 11 days
27 Apr 2021, 05:32
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Let's assume work to be 220 units. Work done by A,B,C per day is 20,11 and 4 respectively. Since B and C work on alternate days. Hence work done in 2 days = 2*A+B+C = 55. Total work to be done in 220. Hence we need 4 cycles of 2 days. Hence 8.
11 Jun 2021, 00:53
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hi bunuel,
i have a question.
total task is 220 units.
speeds
A=20
B=11
C=4 all speeds in units per day.
_ _ _ _ _ _ _ = 7 days
the above dashs are the days.
A= 20*7 = 140
B and C assist on 1st,3rd,5th and 7th day.
so basically - 15*4 = 60 units
140 + 60 = 220 units
the task finishes in 7 days.
please advice
i have a question.
total task is 220 units.
speeds
A=20
B=11
C=4 all speeds in units per day.
_ _ _ _ _ _ _ = 7 days
the above dashs are the days.
A= 20*7 = 140
B and C assist on 1st,3rd,5th and 7th day.
so basically - 15*4 = 60 units
140 + 60 = 220 units
the task finishes in 7 days.
please advice
