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Bunuel
Two buses travel to a place at 45 km/h and 60 km/h, respectively. If the second bus takes 5 1/2 hours less than the first for the journey, the length of the journey is:

(A) 900 km
(B) 945 km
(C) 990 km
(D) 1350 km
(E) 1400 km
Solution:

Since the distance is the same for each bus, we can equate the two distances traveled. If we let x = the number of hours for the first (slower) bus, we see that the faster bus took 5.5 hours less than the slower bus, so the time for the faster bus is (x - 5.5). We can create the equation:

45x = 60(x - 5.5)

45x = 60x - 330

330 = 15x

22 = x

Therefore, the journey is 45(22) = 990 km long.

Answer: C
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Bunuel
Two buses travel to a place at 45 km/h and 60 km/h, respectively. If the second bus takes 5 1/2 hours less than the first for the journey, the length of the journey is:

(A) 900 km
(B) 945 km
(C) 990 km
(D) 1350 km
(E) 1400 km
ATQ,
\(\frac{X}{45}\) - \(\frac{X}{60}\) = \(\frac{11}{2}\)
X = 990 Km

Ans. C
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