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We have an unknown variable: file size.

Let us have a common number that is divisible by 2.5, 4, and 40: 2.5 * 4 * 40 =400

Let's say the initial size of the file is 400 MB.

A + B + C = 2.5 hours = 400 MB file

Rate(A + B + C): \(\frac{400 }{ 2.5}\) = 160 MB per hour

A + C = 4 hours - 400 MB file

Rate(A + C): \(\frac{400 }{ 4}\) = 100 MB per hour


Rate B = Rate (A + B + C) - Rate (A + C) = 160 - 100 = 60MB per hour

File size reduced: \(\frac{1}{40} * 400\) = 10 MB

Time taken by B: \(\frac{10 }{ 60}\) = \(\frac{1}{6}\) hour = \(\frac{1}{6} * 60 = 10\) minutes

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can someone provide answer to this?

Answer should be D: 10 minutes

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Given: Bill downloads the movie "Revenge of the Avengers" to his computer in 2.5 hours, using a download manager that downloads from 3 sources marked A, B and C. Each source provides download at a constant rate, but the rates of different sources are not necessarily identical. If the movie was downloaded from sources A and C alone, it would take 4 hours to complete the download. The next day, source B is available, but the other sources are inactive.

Asked: How long will it take to download the trailer of the movie, a file that is 40 times smaller, from source B alone?

Let the size of the trailer be x GB.
Size of the movie "Revenge of the Avengers" = 40x GB.

Rate of download from sources A, B & C combined = 40x/2.5 = 16x GB/hour
Rate of download from sources A & B combined = 40x/4 = 10x GB/hour
Rate of download from source C alone = 16x - 10x = 6x GB/hour

Time taken to download trailer using source C alone = x/6x hour = 10 minutes

IMO D
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