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08 Jun 2021, 04:45
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B
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Difficulty:
5%
(low)
Question Stats:
90% (01:16) correct
10%
(02:01)
wrong
based on 50
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The average of a set of five values is 12. If one number is deleted, the average of the set is decreased by 0.6. What is the value of the deleted number?
(A) 14.2
(B) 14.4
(C) 16.2
(D) 19.6
(E) 20.2
(A) 14.2
(B) 14.4
(C) 16.2
(D) 19.6
(E) 20.2
08 Jun 2021, 04:54
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Bunuel
Let a, b, c, d and e be the 5 numbers
The average of a set of five values is 12.
We can write: \(\frac{a+b+c+d+e}{5} = 12\)
Multiply both sides by 5 to get: \(a+b+c+d+e=60\)
If one number is deleted, the average of the set is decreased by 0.6
In other words, if e is deleted, the average of the 4 remaining numbers is 11.4
We can write: \(\frac{a+b+c+d}{4} = 11.4\)
Multiply both sides by 4 to get: \(a+b+c+d=45.6\)
What is the value of the deleted number?
We have:
\(a+b+c+d+e=60\)
\(a+b+c+d=45.6\)
Subtract the bottom equation from the top equation to get: \(e = 14.4\)
Answer: B
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