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08 Jun 2021, 06:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:31) correct
16%
(01:45)
wrong
based on 109
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In a class having 60% girls, 40% of the students qualified in a test. If 50% of the girls qualified, find the number of boys who did not qualify in the test as a percentage of the total strength of the class?
(A) 10%
(B) 30%
(C) 45%
(D) 55%
(E) 90%
(A) 10%
(B) 30%
(C) 45%
(D) 55%
(E) 90%
08 Jun 2021, 06:38
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Bunuel
Solution:
Let the total strength of the class be 100.
Then, the total number of girls = 60% of 100 = 60 and the total number of boys = 100 - 60 = 40
• Total number of students who qualified the test = 40% of the total strength
- = 40% of 100 = 40
- = 50% of 60 = 30
- = 40 - 30 = 10
- = 40 - 10
- = 30
Now, percentage of boys who did not qualify = \(\frac{Number of boys who did not qualify}{Total strength of the class}\)*100
- = \(\frac{30}{100}\)*100
= 30%
Hence, the correct answer is Option B.
08 Jun 2021, 06:52
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total students is 100.
girls=(100*60%)=60
Boys=(100-60)=40
40% qualified=(100*40%)=40
50% girls qualified=(60*50%)=30
Boys who qualified=(40-30)=10
boys who did not qualify=(40-10)=30.
So 30% will be the result.
Posted from my mobile device
girls=(100*60%)=60
Boys=(100-60)=40
40% qualified=(100*40%)=40
50% girls qualified=(60*50%)=30
Boys who qualified=(40-30)=10
boys who did not qualify=(40-10)=30.
So 30% will be the result.
Posted from my mobile device
