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09 Jun 2021, 08:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
88% (01:53) correct
12%
(01:43)
wrong
based on 43
sessions
History
Date
Time
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Not Attempted Yet
In colony A, there are 12 houses with an average of 4 members per house, while in colony B, there are 20 houses with an average of Y members per house. If the two colonies together have an average of 3.5 members per house, find Y.
(A) 3.2
(B) 3.6
(C) 4.8
(D) 5.4
(E) 6.2
(A) 3.2
(B) 3.6
(C) 4.8
(D) 5.4
(E) 6.2
Archit3110
Major Poster
09 Jun 2021, 08:28
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from given info we have
12*4+20*y = 3.5*(12+20)
solve for y
3.2
option A
12*4+20*y = 3.5*(12+20)
solve for y
3.2
option A
Bunuel
09 Jun 2021, 08:40
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Sum of members both Colonies A & B = 12 x 4 + 20 x y = 48 + 20y
Total number of houses = 12 + 20 =32
Average of A&B together = 3.5
48 + 20Y = 32 x 3.5
20y = 112 - 48 = 64
y = 64/20 = 3.2
Total number of houses = 12 + 20 =32
Average of A&B together = 3.5
48 + 20Y = 32 x 3.5
20y = 112 - 48 = 64
y = 64/20 = 3.2
