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09 Jun 2021, 08:45
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A
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Difficulty:
5%
(low)
Question Stats:
95% (00:48) correct
5%
(01:48)
wrong
based on 39
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The price of two cups, seven pans and four saucers is Rs. 110 while of one cup and two saucers is Rs. 20. Find the price of three pans.
(A) 30
(B) 40
(C) 60
(D) 70
(E) 80
(A) 30
(B) 40
(C) 60
(D) 70
(E) 80
09 Jun 2021, 08:52
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- • \(2*cup + 7*pans + 4*saucers = 110…(i)\)
• \(1*cup+2*saucer = 20…(ii)\)
- • \(7*pans = 70\)
o \(3*pan = \frac{70}{7}*3 = 30\)
09 Jun 2021, 08:57
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Two equations can be formed
2c + 7p + 4s = 110 ..........(1)
c + 2s = 20 ..........(2)
Multiplying 2nd equation with 2, we will get
2c + 4s = 40 ..........(2)
Subtracting equations 1 and 2, we will get
7p = 70
So, for three pans price will be Rs. 30
i.e Answer is A
Posted from my mobile device
2c + 7p + 4s = 110 ..........(1)
c + 2s = 20 ..........(2)
Multiplying 2nd equation with 2, we will get
2c + 4s = 40 ..........(2)
Subtracting equations 1 and 2, we will get
7p = 70
So, for three pans price will be Rs. 30
i.e Answer is A
Posted from my mobile device
