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10 Jun 2021, 06:45
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (00:58) correct
24%
(01:12)
wrong
based on 210
sessions
History
Date
Time
Result
Not Attempted Yet
Eleven players are to be selected for a match out of an available list of 14 players. In how many ways can this be done such that the best two identified players are always selected?
(A) 14C11
(B) 12P9
(C) 12C9
(D) 12C9 × 2!
(E) 12C11
(A) 14C11
(B) 12P9
(C) 12C9
(D) 12C9 × 2!
(E) 12C11
11 Jun 2021, 13:06
Kudos
Bookmarks
Bunuel
Since, 2 players are always selected. We can simply remove them from our calculation.
So, now available players = 12
remaining seats = 9
\(12C_9\) = 220, (C) IMO!
12 Jun 2021, 01:44
Kudos
Bookmarks
Bunuel
Solution :
We are given,
- • Total number of players = 14
• Number of players to be selected for the match = 11
- • We first keep the best two players fixed in the team.
• Then, the remaining players out of the total = 14 - 2 = 12
• Now, out of these remaining 12 players, we need to select 9 players (since 2 best players are already selected and kept fixed)
Therefore, the required number of ways = 12C9
Hence, the correct answer is Option C.
