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10 Jun 2021, 08:45
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (01:13) correct
7%
(01:55)
wrong
based on 44
sessions
History
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Time
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A man pays a rent of Rs. 50 for the first day, Rs. 100 for the second day and so on, with the rent on each day being Rs. 50 more than the rent on the previous day. What is the total rent paid for the first 10 days?
(A) 2,750
(B) 2,800
(C) 3,050
(D) 3,100
(E) 3,350
(A) 2,750
(B) 2,800
(C) 3,050
(D) 3,100
(E) 3,350
Archit3110
Major Poster
10 Jun 2021, 08:50
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a = 50
d= 50
n=10
sn = n/2 * (2a+(n-1)*d)
s10 = 5*(100+450)
s10 = 2750
option A
d= 50
n=10
sn = n/2 * (2a+(n-1)*d)
s10 = 5*(100+450)
s10 = 2750
option A
Bunuel
11 Jun 2021, 00:03
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using the formula [\(\frac{n}{2} (2a+(n-1)d]\) for sum of n numbers with difference d and first number being a in the series.
we get
[\(\frac{10}{2} (2*50+(10-1)50]\)
5(100+(9*50))
= 2750
Therefore Answer A
we get
[\(\frac{10}{2} (2*50+(10-1)50]\)
5(100+(9*50))
= 2750
Therefore Answer A
