Bunuel
Which of the following is a perfect square?
(A) 97,474
(B) 1,23,301
(C) 1,37,641
(D) 1,70,567
(E) 1,77,243
I don’t believe GMAT would ever want you to calculate the square roots. So we should be able to eliminate wrong choices by some trick.
Few of them are:
1)
Units digit: The units digit of a perfect square will always be 0, 1, 4, 5, 6, or 9. Any number having a units digit of 2, 3, 7 or 8 will not be a perfect square.
2)
Even number: If there is an even number, last two digits should be divisible by 4.
3)
Multiple of 3: The sum of digits if divisible by 3 and not by 9 will not be a perfect square.
D and E cannot be perfect square as last digits are 7 and 3.
A cannot be a perfect square as last two digits 74 is not divisible by 4.
However, I cannot think immediately of some technique to eliminate one of B or C. It would require to be calculated.
1) Now B is not divisible by 2, 3, 5, or 11 by observation itself. so let us try with the prime 7, 13 and then 17. It is divisible by 17.
123,301=17*7253.
But 7253 is not divisible by 17.
2) Another method could be approximation.
90000<123301<160000, almost in middle of two perfect squares. So, it should be between 300^2 and 400^2, and closer to 350 and having 1 or 9 as units digit.
Let us try 351 => 351*351=123,201.
Hence 123,301 is not a perfect square.
C