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08 Jul 2021, 07:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (02:34) correct
15%
(02:20)
wrong
based on 251
sessions
History
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Not Attempted Yet
Three friends divided a bag of chocolates so that David received a fifth the number of chocolates that Fouad did, and Stina received 80 percent of the total number of chocolates. What is the ratio of the number of chocolates Stina received to the number that David received?
(A) 4 : 3
(B) 8 : 5
(C) 8 : 1
(D) 24 : 1
(E) 80 : 1
(A) 4 : 3
(B) 8 : 5
(C) 8 : 1
(D) 24 : 1
(E) 80 : 1
09 Jul 2021, 23:38
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Bunuel
Let the number that Stina received be 80, David and Fouda received be D and F, and the total be 100.
Thus \(D+F=20.........\frac{F}{5}+F=20...........6F=100..........F=\frac{100}{6}..........D=\frac{F}{5}=\frac{100}{6*5}=\frac{10}{3}\)
Ratio = \(S:D=80:\frac{10}{3}=240:10=24:1\)
D
10 Jul 2021, 08:19
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Bunuel
In case someone wishes to solve this question algebraically:
Let the number of chocolates each friend receives be D, F and S respectively.
Given:
Total = S + D + F(1)
\(D = \frac{1}{5} F\)
\(5D = F\)(2)
\(S = \frac{80}{100} T = \frac{4}{5} T\)(3)
So, \(F + D = \frac{1}{5} T\)(4)
From (2):
\(6D = \frac{T}{5}, D = \frac{T}{30}\)
\(\frac{S}{D} = 4/5T / T/30\)
\(\frac{4}{5 T} * \frac{30}{T}\)
24:1, (D) IMO!
