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09 Jul 2021, 06:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (01:47) correct
30%
(02:19)
wrong
based on 600
sessions
History
Date
Time
Result
Not Attempted Yet
Etienne began to eat 20 cookies at exactly the same time Jacques began making more cookies, one at a time, at a constant rate of 16 cookies per hour. If Etienne ate 20 cookies per hour, after how many hours were there no cookies?
A. 3 hours.
B. 4 hours.
C. 5 hours.
D. 6 hours.
E. 7 hours.
A. 3 hours.
B. 4 hours.
C. 5 hours.
D. 6 hours.
E. 7 hours.
09 Jul 2021, 13:41
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There are 20 cookies to start with. Every hour, Etienne eats 20 cookies, and Jacque cooks 16 more. That's a net loss of 4 cookies every hour.
So after one hour, there are 16 cookies, after two hours, 12 cookies, until after five hours, there are no cookies left.
Algebraically:
20 - 20x + 16x = cookies left.
20 - 4x = cookies left.
How long until 0 cookies left?
20 - 4x = 0
So 20 = 4x
So 5 = x.
So after one hour, there are 16 cookies, after two hours, 12 cookies, until after five hours, there are no cookies left.
Algebraically:
20 - 20x + 16x = cookies left.
20 - 4x = cookies left.
How long until 0 cookies left?
20 - 4x = 0
So 20 = 4x
So 5 = x.
09 Jul 2021, 13:27
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Bunuel
The combined rate is \(20 - 16 = 4\) cookies per hour decreased in count. There are 20 cookies in the beginning, so with this rate it will take \(20/4 = 5\) hours to deplete the cookies.
Ans: C
