Two fair six sided dice are thrown once. Find the probability of getti

Question

Two fair six sided dice are thrown once. Find the probability of getting prime numbers on each dice.

A. 1/9
B. 1/4
C. 1/3
D. 1/2
E. 1/6

ArindamLucky · Answer

IMO B

Cases { (2,2) ,(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)} =9 cases

Total cases =6*6=36

Probability of fav cases =9/36=1/4

IanStewart · Answer

On a die, half of the numbers (2, 3 and 5) are prime, so the probability both dice display prime numbers is (1/2)(1/2) = 1/4.

BrushMyQuant · Answer

Given that Two fair six sided dice are thrown once and We need to Find the probability of getting prime numbers on each dice.

As we are rolling two dice => Number of cases =  6^2  = 36

There are three prime numbers between 1 and 6 and they are 2, 3, 5
( Watch this video  to learn about  Prime Numbers )

Prime numbers can come in the two dice in 3*3 = 9 ways

=> Probability of getting prime numbers on each dice =  \frac{9}{36}  =  \frac{1}{4}

So,  Answer will be B 
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

https://www.youtube.com/watch?v=5PVZYQXet18

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