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Bunuel
\(7(19.99) + 3(19.95) =\)

A 7(19.98) + 3(19.96)
B 8(20.00) + 2(19.89)
C 9(20.00) + 19.89
D 9(20.00) + 19.79
E 10(19.97)

We may split the numbers into their integer portion and decimal portion, for example \(7(19.99) + 3(19.95) = 7*20 - 7*0.01 + 3*20 - 3*0.05 = 7*20 + 3*20 - 7*0.01 - 3*0.05\). The integer portions are all the same, however (all roughly 200), so we want to judge the answer by matching the decimal portion.

We can match the decimals by counting how many cents each choice is missing. We are supposed to miss out on \(7*(-0.01) + 3*(-0.15) = -0.22\), 22 cents in total.

Choice A is missing 7*2 + 3*4 = 14 + 12 = 26 cents so that is incorrect. Choice B is missing 2*11 = 22 cents so that is our answer (we can double-check that the integer portion matches as well).

Ans: B
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Bunuel
\(7(19.99) + 3(19.95) =\)

A 7(19.98) + 3(19.96)
B 8(20.00) + 2(19.89)
C 9(20.00) + 19.89
D 9(20.00) + 19.79
E 10(19.97)


Since the question is asking for an exact answer and not an approximation, I simply multiplied 7*9(last digit of 19.99) + 3*5(last digit of 19/95) = 3 + 5 = 8

Now, we are doing the same for options
A) 7*8 + 3*5 = 6+8 = 14, not the answer
B) 8*0 + 2*9 = 18, the answer
C) 9*0 + 9 = 9, not the answer
D) 9*0 + 9 = 9, not the answer
E) 10*7 = 70, not the answer
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