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Given, "The sum of the digits is 10 and the digit at the ten’s place is bigger than the digit at the unit’s place."
So eliminate A and B

Start checking with C

Difference b/w 64 and 46 = 64-46 =18 and satisfies the condition.
(option c)

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As per the above condition,

10x+y -(10y-x) = 18
9x - 9y = 18
x-y = 2 -i
x+y = 10 -ii

From Equation i and ii,
2x = 12
x = 6
y = 4

So nunber is 64.

C is the answer

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