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Solution:

We need the value of \(16^{7.5} ÷ 8^{3.5} ÷ 2^{7.5}\)

\(⇒ 16^{7.5} ÷ \frac{8^{3.5}}{2^{7.5}}\)

\(⇒ 16^{7.5} \times \frac{2^{7.5}}{8^{3.5}}\)

\(⇒ 2^{4\times 7.5} \times \frac{2^{7.5}}{2^{3\times 3.5}}\)

\(⇒ 2^{30} \times \frac{2^{7.5}}{2^{10.5}}\)

\(⇒ 2^{30+7.5-10.5}\)

\(⇒ 2^{27}\)

Hence the right answer is Option E.


I believe this solution is incorrect.

The answer is A: 2^12.

The equation becomes 2^30 ÷ 2^10.5 ÷ 2^7.5 -> 30-10.5-7.5 = 12 -> 2^12.


Please correct me if I'm wrong.
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Bunuel
\(16^{7.5}÷8^{3.5}÷2^{7.5} =\)

(A) 2^12
(B) 2^14
(C) 2^15
(D) 2^16
(E) 2^27


Since both the opertions are division priority is given from left to right.

First:
\( 16^{7.5}÷8^{3.5} = \frac {8^{7.5}*2^{7.5}}{ 8^{3.5}} = 8^{4}*2^{7.5}\)

Second : \(\frac{8^4*2^{7.5}}{2^{7.5}} = 8^4 = 2^{12} \)

Ans-A

Hope it's clear.
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16^7.5÷8^3.5÷2^7.5

(2^4)^7.5÷(2^3)^3.5÷2^7.5

2^30÷2^10.5÷2^7.5 = 2^30-10.5-17.5 = 2^30-18 = 2^12 (A)
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