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09 Sep 2021, 02:50
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
95% (00:40) correct
5%
(01:43)
wrong
based on 40
sessions
History
Date
Time
Result
Not Attempted Yet
Define \(a \# b\) to be \(a^3 – 1\). What is the value of x # 1 ?
(A) 0
(B) \(a^3\)
(C) \(x^3 – 1\)
(D) \(x^3 + 1\)
(E) 2
(A) 0
(B) \(a^3\)
(C) \(x^3 – 1\)
(D) \(x^3 + 1\)
(E) 2
12 Sep 2021, 10:00
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Bunuel
Given: \(a \# b = a^3 – 1\) notice that the second value, b, is totally ignored in the calculation
So, \(x \# 1 = x^3 – 1\)
Answer: C
General Discussion
12 Sep 2021, 11:32
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Given, a#b=a^3 - 1
we can deduce that a#b = (a^3) - (b^0)
similarly, for given equation
==> x#1= (x^3) - (1^0)
IMO C is the answer
Hit kudos if you like the solution
we can deduce that a#b = (a^3) - (b^0)
similarly, for given equation
==> x#1= (x^3) - (1^0)
IMO C is the answer
Hit kudos if you like the solution
