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01 Oct 2021, 04:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
61% (01:25) correct
39%
(01:30)
wrong
based on 188
sessions
History
Date
Time
Result
Not Attempted Yet
Suppose n is a positive integer such that the smallest whole number that is greater than or equal to \(\frac{n}{33}\) is 1 or 2. Which are possible values for the integer n ?
I. 15
II. 66
III. 70
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
I. 15
II. 66
III. 70
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
03 Oct 2021, 20:16
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Bunuel
The largest value of n will be
\(\frac{n}{33}=2…….n=66\)
The smallest value will be 1, as 0/33 will make it equal to 0.
Possible values: 1 to 66
I and II are correct.
D
03 Oct 2021, 21:57
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Bunuel
if n=15 then 15/33 will be <1 and the number smallest number just greater will be 1
if n=66 then 66/33 gives 2 therefore possible
However when n=75 , 75/33 gives a number greater than 2 therefore out
THerefore IMO D
