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Bunuel
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Three lottery winners—X, Y, and Z—are sharing a lottery jackpot. X’s 05 Oct 2021, 07:00
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91% (02:04) correct 9% (03:18) wrong based on 32 sessions

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Three lottery winners—X, Y, and Z—are sharing a lottery jackpot. X’s share is \(\frac{1}{5}\) of Y’s share and \(\frac{1}{7}\) of Z’s share. If the total jackpot is $195,000, what is the dollar amount of Z’s share?

(A) $15,000
(B) $35,000
(C) $75,000
(D) $105,000
(E) $115,000
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D
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GMAT 1: 780 Q51 V45
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Three lottery winners—X, Y, and Z—are sharing a lottery jackpot. X’s 05 Oct 2021, 07:06
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Bunuel
Three lottery winners—X, Y, and Z—are sharing a lottery jackpot. X’s share is \(\frac{1}{5}\) of Y’s share and \(\frac{1}{7}\) of Z’s share. If the total jackpot is $195,000, what is the dollar amount of Z’s share?

(A) $15,000
(B) $35,000
(C) $75,000
(D) $105,000
(E) $115,000
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We can write every other variable in terms of Z. X's share is \(\frac{Z}{7}\). \(\frac{1}{5}\) of Y’s share is equal to \(\frac{1}{7}\) of Z’s share, so we have \(Y = \frac{5}{7}Z\).

Then \(X + Y+ Z = \frac{1}{7}Z + \frac{5}{7}Z + Z = \frac{13}{7}Z = 195,000\)

\(Z = \frac{195,000}{13} * 7 = 15,000*7 = 105,000\)

Ans: D
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Three lottery winners—X, Y, and Z—are sharing a lottery jackpot. X’s 05 Oct 2021, 07:28
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Correct Option D - z = 105000/-

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