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05 Oct 2021, 07:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
91% (02:04) correct
9%
(03:18)
wrong
based on 32
sessions
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Three lottery winners—X, Y, and Z—are sharing a lottery jackpot. X’s share is \(\frac{1}{5}\) of Y’s share and \(\frac{1}{7}\) of Z’s share. If the total jackpot is $195,000, what is the dollar amount of Z’s share?
(A) $15,000
(B) $35,000
(C) $75,000
(D) $105,000
(E) $115,000
(A) $15,000
(B) $35,000
(C) $75,000
(D) $105,000
(E) $115,000
05 Oct 2021, 07:06
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Bunuel
We can write every other variable in terms of Z. X's share is \(\frac{Z}{7}\). \(\frac{1}{5}\) of Y’s share is equal to \(\frac{1}{7}\) of Z’s share, so we have \(Y = \frac{5}{7}Z\).
Then \(X + Y+ Z = \frac{1}{7}Z + \frac{5}{7}Z + Z = \frac{13}{7}Z = 195,000\)
\(Z = \frac{195,000}{13} * 7 = 15,000*7 = 105,000\)
Ans: D
05 Oct 2021, 07:28
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Correct Option D - z = 105000/-
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