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Bunuel
Let A be (0, 0) and B be (10, 0). A semicircle is constructed with AB as diameter, and C is a point on the circumference such that BC = 8 cm. What are the coordinates of point C?

(A) (10, 8)
(B) (4.4, 5.6)
(C) (2.8, 6.4)
(D) (6.4, 3.6)
(E) (3.6, 4.8)


Center of the circle is (5,0)
Radius of the circle is 5 units.

Equation of the circle= (x-5)^2+(y-0)^2= 5^2

(x-5)^2+(y-0)^2= 25
Any point on the circumference will satisfy the equation.

A- (10-5)^2+(8-0)^2=25
LHS is not equal to RHS.

and so On.

Only E satisfies the equation.

Answer is E.
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Bunuel
Let A be (0, 0) and B be (10, 0). A semicircle is constructed with AB as diameter, and C is a point on the circumference such that BC = 8 cm. What are the coordinates of point C?

(A) (10, 8)
(B) (4.4, 5.6)
(C) (2.8, 6.4)
(D) (6.4, 3.6)
(E) (3.6, 4.8)



This question is a part of Are You Up For the Challenge: 700 Level Questions collection.
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Bunuel
Let A be (0, 0) and B be (10, 0). A semicircle is constructed with AB as diameter, and C is a point on the circumference such that BC = 8 cm. What are the coordinates of point C?

(A) (10, 8)
(B) (4.4, 5.6)
(C) (2.8, 6.4)
(D) (6.4, 3.6)
(E) (3.6, 4.8)
It is a logical question and requires no calculation. AB is the diameter with length 10 as shown so radius is 5.
C is on the circumference such that BC is 8 which means C is somewhere as shown in the figure. Why?
BA is 10 so if C were at A, BC would be 10. As we keep moving C closer to B on the circumference, BC will become smaller and will become 8 at a point in the region shown. After all, if C were at (5, 5) then BC would be \(5\sqrt{2}\), which is less than 7.5. So BC would be 8 before C reaches (5, 5).

In the region where C will lie, y co-ordinate is greater than x co-ordinate but still less than 5. There is only 1 such option which is (E)

Answer (E)
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