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13 Oct 2021, 06:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:26) correct
29%
(02:42)
wrong
based on 377
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If \(x=\sqrt[3]{\left(\frac{0.000125}{64}\right)^{-2}}\), what is the value of x?
A) 6400
B) 8000
C) 12500
D) 15625
E) 22500
A) 6400
B) 8000
C) 12500
D) 15625
E) 22500
13 Oct 2021, 16:55
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Bunuel
\(x=\sqrt[3]{\left(\frac{0.000125}{64}\right)^{-2}} = \sqrt[3]{\left(\frac{125 * 10^{-6}}{2^6}\right)^{-2}} = \left(\frac{5^3 * 10^{-6}}{2^6}\right)^{-\frac{2}{3}} = 5^{-2}*10^{4}*2^4 = \frac{16}{25}*10^4 = 16*4*10^2 = 6400\).
Answer: A
