Bunuel

The figure above shows a solid cube 3 inches on a side but with a 1-inch square hole cut through it. How many square inches is the total surface area of the resulting solid figure?
(A) 24
(B) 42
(C) 52
(D) 58
(E) 64
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AmandeepSingh0796 has already done a fabulous job, just adding the figure for a bit more clarity.
Please refer to the picture below:
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Cube .png [ 48.62 KiB | Viewed 1620 times ]
Imagine a white colored cube is completely immersed in a bucket of green paint, and then removed.
The whole outer surface of the cube would then be painted Green.
Now if we remove a portion of the cube as described in the question, the removed portion would look like the portion as shown in fig. \(2\) above.
Initially before operation " cutting a rectangle out " the total surface area of the cube is :
\(6* s^2 \) where \(s\) is a side of a cube , hence \(6* (3)^2 = 54\)
Now when we remove a rectange as shown in the fig above , the remaining cube has a surface area:
\(9+9+9+9+(9-1)+(9-1) -\) > four surfaces remain intact , from other \(2\) surfaces we remove \(1\) sq. inch
\(= 52 \)
Additionally we are left with extra four rectangles that are part of the original cube,each of area \(3*1\), these are shown as unpainted in the second fig. hence \(4*3*1= 12 \)
So now total surface area of the original cube after the operation = \(52 +12 =64\)
Total surface area actually increases since after the removal, we have \(4\) extra rectangles that form inside of the original cube.
Ans E
Hope it's clear.