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Bunuel
What is the thousandths digit in the decimal equivalent of \(\frac{19}{9500}+\frac{95}{4750}\) ?

A. 0
B. 1
C. 2
D. 3
E. 5
\(\frac{19}{9500}+\frac{95}{4750}\)

Or, \(\frac{1}{500} + \frac{1}{50}\)

Or, \(\frac{1+10}{500}\)

Or, \(\frac{11}{500}\)

Or, \(0.022\), Answer must be (C)
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Answer: C

19/9500 + 95/4750
= 1/500 + 1/50
= .002 + .02
= .022

Therefore, Thousandths digit in decimal equivalent = 2
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What is the thousandths digit in the decimal equivalent of \(\frac{19}{9500}+\frac{95}{4750}\) ?

A. 0
B. 1
C. 2
D. 3
E. 5
 



This question is a part of Are You Up For the Challenge: 700 Level Questions collection.­
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