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19 Oct 2021, 02:30
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B
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Difficulty:
55%
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Question Stats:
64% (01:55) correct
36%
(02:06)
wrong
based on 445
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What is the minimum value of z for which \(z^2 + z - \frac{3}{4} > 0\) is not true?
(A) -5/2
(B) -3/2
(C) -1/2
(D) 1/4
(E) 1/2
(A) -5/2
(B) -3/2
(C) -1/2
(D) 1/4
(E) 1/2
24 Nov 2021, 22:54
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For Z = (-5/2), The expression is greater than 0.
For Z = (-3/2), The expression is equal to 0. And Z = -3/2 is the minimum value of Z among the remaining 3 options. Hence B is the answer.
For Z = (-3/2), The expression is equal to 0. And Z = -3/2 is the minimum value of Z among the remaining 3 options. Hence B is the answer.
28 Nov 2021, 07:59
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\(z^2 + z - \frac{3}{4} > 0\)
Factorization will give us:
z^2 + 3/2z - 1/2z -3/4 > 0
z(z+3/2) -1/2(z + 3/2) > 0
So the coordinates are: -3/2 and 1/2
So x has to be > -3/2 not =-3/2 hence -3/2 i.e B is the answer.
Factorization will give us:
z^2 + 3/2z - 1/2z -3/4 > 0
z(z+3/2) -1/2(z + 3/2) > 0
So the coordinates are: -3/2 and 1/2
So x has to be > -3/2 not =-3/2 hence -3/2 i.e B is the answer.
