Bunuel
xx is a two digit integer, the first term of a sequence of consecutive odd positive integers. If the sum of xx and the last term equals 100, and the product of xx and the last term is a number whose four digits equal, in order, x-1, x-1, x-2, x-2, then what is the sum of the four digits?
A. 6
B. 10
C. 14
D. 18
E. 22
Best is to use options.
So sum = x-1 + x-1 + x-2 + x-2 = 4x-6
As xx is odd, x has to be odd.
A. 4x-6 = 6 ……….x=3
Thus, the number is 33, and the last term is 100-33 = 67.
33*67 = 2211…YES
Let us test others too.
B. 4x-6 = 10 ……….x=4.. DISCARD as x is not odd. But we can still check, if say question did not mention odd.
Thus, the number is 44, and the last term is 100-44 = 56.
44*56: NO as the units digit will be 4, while it should be x-2 or 2
C. 4x-6 = 14 ……….x=5
Thus, the number is 55, and the last term is 100-55 = 45.
55*45: NO as the units digit will be 5, while it should be x-2 or 3
D. 4x-6 = 18 ……….x=6 .. DISCARD as x is not odd. But we can still check, if say question did not mention odd.
Thus, the number is 66, and the last term is 100-66 = 34.
66*34: the units digit will be 4, which would be ok, but 66*34 will never be 5abc or 5544.
B. 4x-6 = 22 ……….x=7
Thus, the number is 77, and the last term is 100-77 = 23.
77*23: NO as the units digit will be 1, while it should be x-2 or 5
A