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Bunuel
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Solution Y consists of water and liquid X. The ratio of water to X in 30 Nov 2021, 08:15
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D
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35% (medium)

Question Stats:

64% (01:34) correct 36% (01:56) wrong based on 123 sessions

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Solution Y consists of water and liquid X. The ratio of water to X in 28 kg of solution Y is 2 to 5. If 2 kg of water are added to the solution, what is the ratio of liquid X and water in the new solution?

(A) 1:2

(B) 1:3

(C) 1:1

(D) 2:1

(E) 3:1
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D
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Solution Y consists of water and liquid X. The ratio of water to X in 30 Nov 2021, 09:52
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Bunuel
Solution Y consists of water and liquid X. The ratio of water to X in 28 kg of solution Y is 2 to 5. If 2 kg of water are added to the solution, what is the ratio of liquid X and water in the new solution?

(A) 1:2

(B) 1:3

(C) 1:1

(D) 2:1

(E) 3:1
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Water:X = 2:5
In 28 kg solution, water = 28*\(\frac{2}{7}\) = 8Kg
X = 28-8 = 20 kg
Add 2 kg water, water increase to 10 kg.
X:Water = 20:10 = 2:1
Ans. D
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Solution Y consists of water and liquid X. The ratio of water to X in 30 Nov 2021, 10:27
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Hope this explanation helps! :)

https://youtu.be/7WCYGI37WxQ
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Solution Y consists of water and liquid X. The ratio of water to X in 30 Nov 2021, 18:52
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Bunuel
Solution Y consists of water and liquid X. The ratio of water to X in 28 kg of solution Y is 2 to 5. If 2 kg of water are added to the solution, what is the ratio of liquid X and water in the new solution?

(A) 1:2

(B) 1:3

(C) 1:1

(D) 2:1

(E) 3:1
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Breaking Down the Info:

The ratio of \(Water:X:Y\) is \(2:5:7\). Then we know \(\frac{2}{7}\) of Y is water, hence \(\frac{2}{7}*28 = 8 \text{ kg}\) is water.

After adding 2 kg of water, we would have 10 kg water and 20 kg of X. Then the ratio is \(20:10 = 2:1\).

Answer: D
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Solution Y consists of water and liquid X. The ratio of water to X in 25 Aug 2023, 11:53
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Solution Y consists of water and liquid X. The ratio of water to X in 28 kg of solution Y is 2 to 5. If 2 kg of water are added to the solution, what is the ratio of liquid X and water in the new solution?

Quantity of Water in Solution Y = (2/[2+5]) * 28 = (2/7) * 28 = 8 kg
Now, Quantity of liquid X in Solution Y = 28-8 = 20 kg

After modification,
Quantity of Water in Solution Y = 8 + 2 = 10 kg

Ration of liquid X and water in the new solution = 20:10=2:1

Hence D
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