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22 Dec 2021, 02:30
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
84% (02:32) correct
16%
(02:35)
wrong
based on 146
sessions
History
Date
Time
Result
Not Attempted Yet
Starting from city A, car X sets out towards city B at a constant speed of 45 miles per hour. Twenty minutes after car X starts, car Y sets out from city A towards city B, also traveling at a constant speed. If it takes exactly 40 minutes for car Y to catch up to car X, at what speed is car Y traveling?
A. 75
B. 70
C. 67.5
D. 57
E. 50
A. 75
B. 70
C. 67.5
D. 57
E. 50
22 Dec 2021, 03:44
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Bunuel
Sometimes I don't know I should feel proud doing so or just a prick.!
Bunuel I think in the last part of the sentence it should be at what speed car 'Y' is traveling instead of the speed of car 'X' because the speed of car X is already given.
Now to answer the question:
Speed of Car X = 45miles/hour
Distance covered in 20 minutes = 45*20/60 = 15miles.
After which car Y started to travel in the same direction, let its speed be Y.
So relative speed = Y-45
It takes 40 minutes to cover the distance so the equation will be:
(Y-45)40/60 = 15
Y-45 = 22.5
Y = 67.5 Option C
28 Dec 2021, 09:40
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Bunuel
For A,
60 min. = 45 Km
20 min. = 15 Km
This 15 Km was covered by B in 40 mins.
40 min. = 15 Km
60 min. = 22.5 Km.
This 22.5 Km was additional speed to A's speed to find the speed of B.
B's speed = 45 + 22.5= 67.5 Km
