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03 Jan 2022, 07:37
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
56% (01:21) correct
44%
(01:57)
wrong
based on 36
sessions
History
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Not Attempted Yet
A fountain having the shape of a right circular cone is fitted into a cylindrical tank of volume V, so that the base of the tank coincides with the base of the cone and the height of the tank is the same as that of the cone. The volume of water in the tank, when it is completely filled with water from the fountain is?
a. V/3
b. V/4
c. 2V/3
d. V/2
e. V/6
Posted from my mobile device
a. V/3
b. V/4
c. 2V/3
d. V/2
e. V/6
Posted from my mobile device
09 Jan 2022, 05:18
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Mugdho
Given \( \pi r^2 h = v\\
\)
The volume of water will be \( \pi r^2h - \frac{1}{3}\pi r^2h = \frac{2}{3}\pi r^2h = \frac{2}{3}v \)
Ans =B
Hope it's clear.
09 Jan 2022, 08:54
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If you know that the Volume of a Cone is (1/3rd) the Volume of a Right Circular Cylinder, then you know what this question is basically testing.
Volume of any right circular cone with same height and same radius = (1/3) (Volume of corresponding cylinder)
The cone takes up (1/3)V inside the cylinder
Thus: V - (1/3)V = (2/3)V remains inside the cylinder to be filled with water
2V/3
Posted from my mobile device
Volume of any right circular cone with same height and same radius = (1/3) (Volume of corresponding cylinder)
The cone takes up (1/3)V inside the cylinder
Thus: V - (1/3)V = (2/3)V remains inside the cylinder to be filled with water
2V/3
Posted from my mobile device
